1/3(12z+18z^2)

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Solution for 1/3(12z+18z^2) equation: 


z in (-oo:+oo)

(1/3)*(18*z^2+12*z) = 0

1/3*(18*z^2+12*z) = 0

18*z^2+12*z = 0

6*z*(3*z+2) = 0

3*z+2 = 0 // - 2

3*z = -2 // : 3

z = -2/3

6*z*(z+2/3) = 0

1/3*6*z*(z+2/3) = 0

( 6*z )

6*z = 0 // : 6

z = 0

( z+2/3 )

z+2/3 = 0 // - 2/3

z = -2/3

z in { 0, -2/3 }

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